401. Binary Watch
Problem description:
A binary watch has 4 LEDs on the top which represent the hours (0-11), and the 6 LEDs on the bottom represent the minutes (0-59).
Each LED represents a zero or one, with the least significant bit on the right.
For example, the above binary watch reads “3:25”.
Given a non-negative integer n which represents the number of LEDs that are currently on, return all possible times the watch could represent.
Example:
Input: n = 1
Return: [“1:00”, “2:00”, “4:00”, “8:00”, “0:01”, “0:02”, “0:04”, “0:08”, “0:16”, “0:32”]
Note:
The order of output does not matter.
The hour must not contain a leading zero, for example “01:00” is not valid, it should be “1:00”.
The minute must be consist of two digits and may contain a leading zero, for example “10:2” is not valid, it should be “10:02”.
Solution:
We can use backtracking to solve this problem.
- Think
hours
andminutes
as a combined array. - Like a combination problem. If we want to pick
n
elements fromhours
andminutes
, we will pickn-i
elements fromminutes
while we picki
elements fromhours
.
- example: if n= 2:
1
2
3
4["3:00","5:00","9:00","1:01","1:02", ...]`
1+2:00 ,1+4:00,1+8:00, 1:01
i=4(equal to hour.size())
generate minute then call helper again
1 | class Solution { |
reference: