304. Range Sum Query 2D - Immutable
Problem description:
Given a 2D matrix matrix, find the sum of the elements inside the rectangle defined by its upper left corner (row1, col1) and lower right corner (row2, col2).
The above rectangle (with the red border) is defined by (row1, col1) = (2, 1) and (row2, col2) = (4, 3), which contains sum = 8.
Example:1
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11Given matrix = [
[3, 0, 1, 4, 2],
[5, 6, 3, 2, 1],
[1, 2, 0, 1, 5],
[4, 1, 0, 1, 7],
[1, 0, 3, 0, 5]
]
sumRegion(2, 1, 4, 3) -> 8
sumRegion(1, 1, 2, 2) -> 11
sumRegion(1, 2, 2, 4) -> 12
Note:
You may assume that the matrix does not change.
There are many calls to sumRegion function.
You may assume that row1 ≤ row2 and col1 ≤ col2.
Solution:
Construct a 2D array sums[row+1][col+1]
(notice: we add additional blank row sums[0][col+1]={0} and blank column sums[row+1][0]={0} to remove the edge case checking), so, we can have the following definition
sums[i+1][j+1] represents the sum of area from matrix[0][0] to matrix[i][j]
To calculate sums, the ideas as below
1 | +---------------+ +--------------+ +---------------+ +--------------+ +--------------+ |
1 | class NumMatrix: |
1 | class NumMatrix { |
time complexity: preprocess: $O(mn)$, query: $O(1)$
space complexity: $O(mn)$
reference:
https://goo.gl/t9pi4v
https://goo.gl/jDo3CY