Problem description:

Design a hit counter which counts the number of hits received in the past 5 minutes (i.e., the past 300 seconds).

Your system should accept a timestamp parameter (in seconds granularity), and you may assume that calls are being made to the system in chronological order (i.e., timestamp is monotonically increasing). Several hits may arrive roughly at the same time.

Implement the HitCounter class:

  • HitCounter() Initializes the object of the hit counter system.
  • void hit(int timestamp) Records a hit that happened at timestamp (in seconds). Several hits may happen at the same timestamp.
  • int getHits(int timestamp) Returns the number of hits in the past 5 minutes from timestamp (i.e., the past 300 seconds).

Example 1:

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Input
["HitCounter", "hit", "hit", "hit", "getHits", "hit", "getHits", "getHits"]
[[], [1], [2], [3], [4], [300], [300], [301]]
Output
[null, null, null, null, 3, null, 4, 3]

Explanation
HitCounter hitCounter = new HitCounter();
hitCounter.hit(1); // hit at timestamp 1.
hitCounter.hit(2); // hit at timestamp 2.
hitCounter.hit(3); // hit at timestamp 3.
hitCounter.getHits(4); // get hits at timestamp 4, return 3.
hitCounter.hit(300); // hit at timestamp 300.
hitCounter.getHits(300); // get hits at timestamp 300, return 4.
hitCounter.getHits(301); // get hits at timestamp 301, return 3.

Constraints:

  • 1 <= timestamp <= 2 * 109
  • All the calls are being made to the system in chronological order (i.e., timestamp is monotonically increasing).
  • At most 300 calls will be made to hit and getHits.

Follow up: What if the number of hits per second could be huge? Does your design scale?

Solution:

Two ways to implement

  1. Circular array
  2. Queue

circular array might be better in huge amount of hit count

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class HitCounter:

def __init__(self):
self.q = [(0, 0)]*300 # (freq, time)

def hit(self, timestamp: int) -> None:
"""
Record a hit.
@param timestamp - The current timestamp (in seconds granularity).
"""
idx = timestamp % 300
time, hit = self.q[idx]
if time != timestamp:
self.q[idx] = timestamp, 1
else:
self.q[idx] = time, hit + 1

def getHits(self, timestamp: int) -> int:
"""
Return the number of hits in the past 5 minutes.
@param timestamp - The current timestamp (in seconds granularity).
"""
ans = 0
for i in range(len(self.q)):
time, hit = self.q[i]
if timestamp - time < 300:
ans += hit
return ans

# Your HitCounter object will be instantiated and called as such:
# obj = HitCounter()
# obj.hit(timestamp)
# param_2 = obj.getHits(timestamp)

time complexity: $O()$
space complexity: $O()$
reference:
related problem: